pixel[1] = pixel[1] 0.0031308f ? 1.055f * powf(pixel[1], 1.0f / 2.4f) - 0.055f : 12.92f * pixel[1];
When I was going through the Invisalign process, I was looking at studies on the efficacy of Invisalign to understand if it is as good as braces, and it seemed like a lot of those studies were done on a narrow demographic group. What are you doing to expand the research, especially as you go into new markets around the world?
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